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Colin B Maharaj
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MySQL syntax for an inverted table2006-10-02 07:30:00 AM cppbuilder23 I have this query (and result)... select desttype A, sum(duration) B, count(cost) C, sum(cost) D from calls group by desttype; +------+----------+--------+---------+ | A | B | C | D | +------+----------+--------+---------+ | NULL | 20179324 | 122048 | 0.00 | | AR | 13155339 | 70456 | 0.00 | | CE | 1385003 | 16232 | 0.00 | | IT | 86003 | 292 | 1814.60 | | LD | 526292 | 2213 | 7438.29 | | LO | 261093 | 557 | 0.00 | | SD | 8684 | 41 | 643.50 | +------+----------+--------+---------+ 7 rows in set (0.56 sec) But I want to turn it "90 degrees" i.e. make the tuples into columns and the columns into tuples. So far this is what I have come up with, partially...... select * from (select sum(cost) AR from calls where desttype='AR') as tmp1, (select sum(cost) LO from calls where desttype='LO') as tmp2, (select sum(cost) LD from calls where desttype='LD') as tmp3, (select sum(cost) IT from calls where desttype='IT') as tmp4; +------+------+---------+---------+ | AR | LO | LD | IT | +------+------+---------+---------+ | 0.00 | 0.00 | 7438.29 | 1814.60 | +------+------+---------+---------+ 1 row in set (1.05 sec) But I think this is way too much processing and this is just the cost part. Any advice would be nice. I am using MySQL 5x. |